Integrand size = 19, antiderivative size = 57 \[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {\cos (c+d x)}{a^2 d}+\frac {b^2}{a^3 d (b+a \cos (c+d x))}+\frac {2 b \log (b+a \cos (c+d x))}{a^3 d} \]
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Time = 0.22 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {3957, 2912, 12, 45} \[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=\frac {b^2}{a^3 d (a \cos (c+d x)+b)}+\frac {2 b \log (a \cos (c+d x)+b)}{a^3 d}-\frac {\cos (c+d x)}{a^2 d} \]
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Rule 12
Rule 45
Rule 2912
Rule 3957
Rubi steps \begin{align*} \text {integral}& = \int \frac {\cos ^2(c+d x) \sin (c+d x)}{(-b-a \cos (c+d x))^2} \, dx \\ & = \frac {\text {Subst}\left (\int \frac {x^2}{a^2 (-b+x)^2} \, dx,x,-a \cos (c+d x)\right )}{a d} \\ & = \frac {\text {Subst}\left (\int \frac {x^2}{(-b+x)^2} \, dx,x,-a \cos (c+d x)\right )}{a^3 d} \\ & = \frac {\text {Subst}\left (\int \left (1+\frac {b^2}{(b-x)^2}-\frac {2 b}{b-x}\right ) \, dx,x,-a \cos (c+d x)\right )}{a^3 d} \\ & = -\frac {\cos (c+d x)}{a^2 d}+\frac {b^2}{a^3 d (b+a \cos (c+d x))}+\frac {2 b \log (b+a \cos (c+d x))}{a^3 d} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.33 \[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=\frac {-a^2 \cos ^2(c+d x)+a b \cos (c+d x) (-1+2 \log (b+a \cos (c+d x)))+b^2 (1+2 \log (b+a \cos (c+d x)))}{a^3 d (b+a \cos (c+d x))} \]
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Time = 0.52 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.18
method | result | size |
derivativedivides | \(\frac {-\frac {1}{a^{2} \sec \left (d x +c \right )}-\frac {2 b \ln \left (\sec \left (d x +c \right )\right )}{a^{3}}-\frac {b}{a^{2} \left (a +b \sec \left (d x +c \right )\right )}+\frac {2 b \ln \left (a +b \sec \left (d x +c \right )\right )}{a^{3}}}{d}\) | \(67\) |
default | \(\frac {-\frac {1}{a^{2} \sec \left (d x +c \right )}-\frac {2 b \ln \left (\sec \left (d x +c \right )\right )}{a^{3}}-\frac {b}{a^{2} \left (a +b \sec \left (d x +c \right )\right )}+\frac {2 b \ln \left (a +b \sec \left (d x +c \right )\right )}{a^{3}}}{d}\) | \(67\) |
risch | \(-\frac {2 i b x}{a^{3}}-\frac {{\mathrm e}^{i \left (d x +c \right )}}{2 a^{2} d}-\frac {{\mathrm e}^{-i \left (d x +c \right )}}{2 a^{2} d}-\frac {4 i b c}{a^{3} d}+\frac {2 b^{2} {\mathrm e}^{i \left (d x +c \right )}}{a^{3} d \left (a \,{\mathrm e}^{2 i \left (d x +c \right )}+2 b \,{\mathrm e}^{i \left (d x +c \right )}+a \right )}+\frac {2 b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+\frac {2 b \,{\mathrm e}^{i \left (d x +c \right )}}{a}+1\right )}{a^{3} d}\) | \(138\) |
parallelrisch | \(\frac {4 \ln \left (-2 a +\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} \left (a -b \right )\right ) a \,b^{2} \cos \left (d x +c \right )-4 \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right ) a \,b^{2} \cos \left (d x +c \right )-2 a^{3} \cos \left (d x +c \right )-4 \cos \left (d x +c \right ) a \,b^{2}+4 \ln \left (-2 a +\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} \left (a -b \right )\right ) b^{3}-a^{2} b \cos \left (2 d x +2 c \right )-4 \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right ) b^{3}-3 a^{2} b}{2 a^{3} d b \left (b +a \cos \left (d x +c \right )\right )}\) | \(171\) |
norman | \(\frac {\frac {2 a^{2}+4 a b +4 b^{2}}{2 d \,a^{2} b}-\frac {\left (2 a^{2}-4 a b +4 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{2 d \,a^{2} b}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b -a -b \right )}-\frac {2 b \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{a^{3} d}+\frac {2 b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b -a -b \right )}{a^{3} d}\) | \(185\) |
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Time = 0.29 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.32 \[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {a^{2} \cos \left (d x + c\right )^{2} + a b \cos \left (d x + c\right ) - b^{2} - 2 \, {\left (a b \cos \left (d x + c\right ) + b^{2}\right )} \log \left (a \cos \left (d x + c\right ) + b\right )}{a^{4} d \cos \left (d x + c\right ) + a^{3} b d} \]
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\[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=\int \frac {\sin {\left (c + d x \right )}}{\left (a + b \sec {\left (c + d x \right )}\right )^{2}}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.96 \[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=\frac {\frac {b^{2}}{a^{4} \cos \left (d x + c\right ) + a^{3} b} - \frac {\cos \left (d x + c\right )}{a^{2}} + \frac {2 \, b \log \left (a \cos \left (d x + c\right ) + b\right )}{a^{3}}}{d} \]
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Time = 0.32 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.07 \[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {\cos \left (d x + c\right )}{a^{2} d} + \frac {2 \, b \log \left ({\left | -a \cos \left (d x + c\right ) - b \right |}\right )}{a^{3} d} + \frac {b^{2}}{{\left (a \cos \left (d x + c\right ) + b\right )} a^{3} d} \]
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Time = 0.08 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.05 \[ \int \frac {\sin (c+d x)}{(a+b \sec (c+d x))^2} \, dx=\frac {b^2}{d\,\left (\cos \left (c+d\,x\right )\,a^4+b\,a^3\right )}-\frac {\cos \left (c+d\,x\right )}{a^2\,d}+\frac {2\,b\,\ln \left (b+a\,\cos \left (c+d\,x\right )\right )}{a^3\,d} \]
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